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3480727617113 is a prime number
BaseRepresentation
bin110010101001101011100…
…010000111111001011001
3110022202100220002111110212
4302221223202013321121
5424012012232221423
611223005120420505
7506321450403305
oct62515342077131
913282326074425
103480727617113
111122193aa770a
12482708777735
131c3300c61906
14c067a71ad05
156081d436578
hex32a6b887e59

3480727617113 has 2 divisors, whose sum is σ = 3480727617114. Its totient is φ = 3480727617112.

The previous prime is 3480727617067. The next prime is 3480727617121. The reversal of 3480727617113 is 3117167270843.

3480727617113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3390912322249 + 89815294864 = 1841443^2 + 299692^2 .

It is a cyclic number.

It is not a de Polignac number, because 3480727617113 - 28 = 3480727616857 is a prime.

It is not a weakly prime, because it can be changed into another prime (3480727617193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1740363808556 + 1740363808557.

It is an arithmetic number, because the mean of its divisors is an integer number (1740363808557).

Almost surely, 23480727617113 is an apocalyptic number.

It is an amenable number.

3480727617113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3480727617113 is an equidigital number, since it uses as much as digits as its factorization.

3480727617113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1185408, while the sum is 50.

The spelling of 3480727617113 in words is "three trillion, four hundred eighty billion, seven hundred twenty-seven million, six hundred seventeen thousand, one hundred thirteen".