Base | Representation |
---|---|
bin | 110010101011111001001… |
… | …001001101101000100011 |
3 | 110022222111110122101210211 |
4 | 302223321021031220203 |
5 | 424031343440423213 |
6 | 11224040551034551 |
7 | 506434356561562 |
oct | 62537111155043 |
9 | 13288443571724 |
10 | 3483103451683 |
11 | 11231a3104359 |
12 | 48307036ba57 |
13 | 1c35bc23919b |
14 | c0824089bd9 |
15 | 6090bcd753d |
hex | 32af924da23 |
3483103451683 has 2 divisors, whose sum is σ = 3483103451684. Its totient is φ = 3483103451682.
The previous prime is 3483103451651. The next prime is 3483103451759. The reversal of 3483103451683 is 3861543013843.
3483103451683 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3483103451683 - 25 = 3483103451651 is a prime.
It is not a weakly prime, because it can be changed into another prime (3483103455683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1741551725841 + 1741551725842.
It is an arithmetic number, because the mean of its divisors is an integer number (1741551725842).
Almost surely, 23483103451683 is an apocalyptic number.
3483103451683 is a deficient number, since it is larger than the sum of its proper divisors (1).
3483103451683 is an equidigital number, since it uses as much as digits as its factorization.
3483103451683 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2488320, while the sum is 49.
The spelling of 3483103451683 in words is "three trillion, four hundred eighty-three billion, one hundred three million, four hundred fifty-one thousand, six hundred eighty-three".
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