Base | Representation |
---|---|
bin | 110010101100110100101… |
… | …111110100000111000001 |
3 | 110100002002011021101101001 |
4 | 302230310233310013001 |
5 | 424040420434121442 |
6 | 11224324112012001 |
7 | 506501221326211 |
oct | 62546457640701 |
9 | 13302064241331 |
10 | 3484103426497 |
11 | 1123666610221 |
12 | 4832ab231001 |
13 | 1c371b467a65 |
14 | c08babcc241 |
15 | 609699b12b7 |
hex | 32b34bf41c1 |
3484103426497 has 2 divisors, whose sum is σ = 3484103426498. Its totient is φ = 3484103426496.
The previous prime is 3484103426467. The next prime is 3484103426513. The reversal of 3484103426497 is 7946243014843.
3484103426497 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2185196454081 + 1298906972416 = 1478241^2 + 1139696^2 .
It is a cyclic number.
It is not a de Polignac number, because 3484103426497 - 223 = 3484095037889 is a prime.
It is not a weakly prime, because it can be changed into another prime (3484103426437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1742051713248 + 1742051713249.
It is an arithmetic number, because the mean of its divisors is an integer number (1742051713249).
Almost surely, 23484103426497 is an apocalyptic number.
It is an amenable number.
3484103426497 is a deficient number, since it is larger than the sum of its proper divisors (1).
3484103426497 is an equidigital number, since it uses as much as digits as its factorization.
3484103426497 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13934592, while the sum is 55.
The spelling of 3484103426497 in words is "three trillion, four hundred eighty-four billion, one hundred three million, four hundred twenty-six thousand, four hundred ninety-seven".
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