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349403 is a prime number
BaseRepresentation
bin1010101010011011011
3122202021212
41111103123
542140103
611253335
72653445
oct1252333
9582255
10349403
1121956a
1214a24b
13c3062
1491495
156d7d8
hex554db

349403 has 2 divisors, whose sum is σ = 349404. Its totient is φ = 349402.

The previous prime is 349399. The next prime is 349409. The reversal of 349403 is 304943.

It is a weak prime.

It is an emirp because it is prime and its reverse (304943) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 349403 - 22 = 349399 is a prime.

It is not a weakly prime, because it can be changed into another prime (349409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 174701 + 174702.

It is an arithmetic number, because the mean of its divisors is an integer number (174702).

2349403 is an apocalyptic number.

349403 is a deficient number, since it is larger than the sum of its proper divisors (1).

349403 is an equidigital number, since it uses as much as digits as its factorization.

349403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

The square root of 349403 is about 591.1032058786. The cubic root of 349403 is about 70.4328955899.

It can be divided in two parts, 34940 and 3, that added together give a palindrome (34943).

The spelling of 349403 in words is "three hundred forty-nine thousand, four hundred three".