Search a number
-
+
3497300594129 is a prime number
BaseRepresentation
bin110010111001000111010…
…111000000110111010001
3110101100010220001221222102
4302321013113000313101
5424244432423003004
611234345425050145
7510446240363456
oct62710727006721
913340126057872
103497300594129
111129219013631
12485972a86955
131c4a426417a4
14c13ad7dd82d
1560e8d3ad11e
hex32e475c0dd1

3497300594129 has 2 divisors, whose sum is σ = 3497300594130. Its totient is φ = 3497300594128.

The previous prime is 3497300594113. The next prime is 3497300594143. The reversal of 3497300594129 is 9214950037943.

3497300594129 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3465312556225 + 31988037904 = 1861535^2 + 178852^2 .

It is a cyclic number.

It is not a de Polignac number, because 3497300594129 - 24 = 3497300594113 is a prime.

It is a super-2 number, since 2×34973005941292 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3497300594189) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1748650297064 + 1748650297065.

It is an arithmetic number, because the mean of its divisors is an integer number (1748650297065).

Almost surely, 23497300594129 is an apocalyptic number.

It is an amenable number.

3497300594129 is a deficient number, since it is larger than the sum of its proper divisors (1).

3497300594129 is an equidigital number, since it uses as much as digits as its factorization.

3497300594129 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7348320, while the sum is 56.

The spelling of 3497300594129 in words is "three trillion, four hundred ninety-seven billion, three hundred million, five hundred ninety-four thousand, one hundred twenty-nine".