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350004113 is a prime number
BaseRepresentation
bin10100110111001…
…010001110010001
3220101121001101022
4110313022032101
51204100112423
654421445225
711446662104
oct2467121621
9811531338
10350004113
1116a6282a8
1299270815
1357688034
14346ac73b
1520ad9dc8
hex14dca391

350004113 has 2 divisors, whose sum is σ = 350004114. Its totient is φ = 350004112.

The previous prime is 350004101. The next prime is 350004139. The reversal of 350004113 is 311400053.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 212809744 + 137194369 = 14588^2 + 11713^2 .

It is a cyclic number.

It is not a de Polignac number, because 350004113 - 216 = 349938577 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 350004091 and 350004100.

It is not a weakly prime, because it can be changed into another prime (350004163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175002056 + 175002057.

It is an arithmetic number, because the mean of its divisors is an integer number (175002057).

Almost surely, 2350004113 is an apocalyptic number.

It is an amenable number.

350004113 is a deficient number, since it is larger than the sum of its proper divisors (1).

350004113 is an equidigital number, since it uses as much as digits as its factorization.

350004113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180, while the sum is 17.

The square root of 350004113 is about 18708.3968580956. The cubic root of 350004113 is about 704.7326337233.

Adding to 350004113 its reverse (311400053), we get a palindrome (661404166).

The spelling of 350004113 in words is "three hundred fifty million, four thousand, one hundred thirteen".