350010010111 has 8 divisors (see below), whose sum is σ = 367829503184. Its totient is φ = 332630504640.

The previous prime is 350010010093. The next prime is 350010010117. The reversal of 350010010111 is 111010010053.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 350010010111 - 2¹⁹ = 350009485823 is a prime.

It is a super-4 number, since 4×350010010111⁴ (a number of 47 digits) contains 4444 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 350010010091 and 350010010100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (350010010117) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 109995270 + ... + 109998451.

It is an arithmetic number, because the mean of its divisors is an integer number (45978687898).

Almost surely, 2^350010010111 is an apocalyptic number.

350010010111 is a deficient number, since it is larger than the sum of its proper divisors (17819493073).

350010010111 is a wasteful number, since it uses less digits than its factorization.

350010010111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 219993801.

The product of its (nonzero) digits is 15, while the sum is 13.

Adding to 350010010111 its reverse (111010010053), we get a palindrome (461020020164).

The spelling of 350010010111 in words is "three hundred fifty billion, ten million, ten thousand, one hundred eleven".