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111010010053 is a prime number
BaseRepresentation
bin110011101100010110…
…1100101001111000101
3101121112110220210200211
41213120231211033011
53304322030310203
6122555225435421
711006634342115
oct1473055451705
9347473823624
10111010010053
1143096290668
121962103bb71
13a6118303a7
1455313b9045
152d4ab04c6d
hex19d8b653c5

111010010053 has 2 divisors, whose sum is σ = 111010010054. Its totient is φ = 111010010052.

The previous prime is 111010010051. The next prime is 111010010093. The reversal of 111010010053 is 350010010111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 107556449764 + 3453560289 = 327958^2 + 58767^2 .

It is a cyclic number.

It is not a de Polignac number, because 111010010053 - 21 = 111010010051 is a prime.

It is a super-2 number, since 2×1110100100532 (a number of 23 digits) contains 22 as substring.

Together with 111010010051, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111010010051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55505005026 + 55505005027.

It is an arithmetic number, because the mean of its divisors is an integer number (55505005027).

Almost surely, 2111010010053 is an apocalyptic number.

It is an amenable number.

111010010053 is a deficient number, since it is larger than the sum of its proper divisors (1).

111010010053 is an equidigital number, since it uses as much as digits as its factorization.

111010010053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15, while the sum is 13.

Adding to 111010010053 its reverse (350010010111), we get a palindrome (461020020164).

The spelling of 111010010053 in words is "one hundred eleven billion, ten million, ten thousand, fifty-three".