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3500114534314 = 21750057267157
BaseRepresentation
bin110010111011101111000…
…101010101111110101010
3110101121101222222221020021
4302323233011111332222
5424321213310044224
611235532545351054
7510606046441636
oct62735705257652
913347358887207
103500114534314
11112a432452532
1248641933848a
131c50a060cb58
14c1599411dc6
15610a544d1e4
hex32eef155faa

3500114534314 has 4 divisors (see below), whose sum is σ = 5250171801474. Its totient is φ = 1750057267156.

The previous prime is 3500114534237. The next prime is 3500114534327. The reversal of 3500114534314 is 4134354110053.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 3429100279089 + 71014255225 = 1851783^2 + 266485^2 .

It is a super-2 number, since 2×35001145343142 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 3500114534314.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 875028633577 + ... + 875028633580.

Almost surely, 23500114534314 is an apocalyptic number.

3500114534314 is a deficient number, since it is larger than the sum of its proper divisors (1750057267160).

3500114534314 is a wasteful number, since it uses less digits than its factorization.

3500114534314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1750057267159.

The product of its (nonzero) digits is 43200, while the sum is 34.

Adding to 3500114534314 its reverse (4134354110053), we get a palindrome (7634468644367).

The spelling of 3500114534314 in words is "three trillion, five hundred billion, one hundred fourteen million, five hundred thirty-four thousand, three hundred fourteen".

Divisors: 1 2 1750057267157 3500114534314