Base | Representation |
---|---|
bin | 110010111011101111000… |
… | …101010101111110101010 |
3 | 110101121101222222221020021 |
4 | 302323233011111332222 |
5 | 424321213310044224 |
6 | 11235532545351054 |
7 | 510606046441636 |
oct | 62735705257652 |
9 | 13347358887207 |
10 | 3500114534314 |
11 | 112a432452532 |
12 | 48641933848a |
13 | 1c50a060cb58 |
14 | c1599411dc6 |
15 | 610a544d1e4 |
hex | 32eef155faa |
3500114534314 has 4 divisors (see below), whose sum is σ = 5250171801474. Its totient is φ = 1750057267156.
The previous prime is 3500114534237. The next prime is 3500114534327. The reversal of 3500114534314 is 4134354110053.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 3429100279089 + 71014255225 = 1851783^2 + 266485^2 .
It is a super-2 number, since 2×35001145343142 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 3500114534314.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 875028633577 + ... + 875028633580.
Almost surely, 23500114534314 is an apocalyptic number.
3500114534314 is a deficient number, since it is larger than the sum of its proper divisors (1750057267160).
3500114534314 is a wasteful number, since it uses less digits than its factorization.
3500114534314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1750057267159.
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 3500114534314 its reverse (4134354110053), we get a palindrome (7634468644367).
The spelling of 3500114534314 in words is "three trillion, five hundred billion, one hundred fourteen million, five hundred thirty-four thousand, three hundred fourteen".
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