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350014142 = 2175007071
BaseRepresentation
bin10100110111001…
…100101010111110
3220101121120010202
4110313030222332
51204100423032
654422003502
711450033252
oct2467145276
9811546122
10350014142
1116a634895
1299276592
135768c77a
14346b2262
1520adcd62
hex14dccabe

350014142 has 4 divisors (see below), whose sum is σ = 525021216. Its totient is φ = 175007070.

The previous prime is 350014141. The next prime is 350014163. The reversal of 350014142 is 241410053.

350014142 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 241410053 = 835328901.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (350014141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 87503534 + ... + 87503537.

It is an arithmetic number, because the mean of its divisors is an integer number (131255304).

Almost surely, 2350014142 is an apocalyptic number.

350014142 is a deficient number, since it is larger than the sum of its proper divisors (175007074).

350014142 is a wasteful number, since it uses less digits than its factorization.

350014142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 175007073.

The product of its (nonzero) digits is 480, while the sum is 20.

The square root of 350014142 is about 18708.6648909002. The cubic root of 350014142 is about 704.7393647833.

Adding to 350014142 its reverse (241410053), we get a palindrome (591424195).

The spelling of 350014142 in words is "three hundred fifty million, fourteen thousand, one hundred forty-two".

Divisors: 1 2 175007071 350014142