Search a number
-
+
350025131 is a prime number
BaseRepresentation
bin10100110111001…
…111010110101011
3220101122010012202
4110313033112223
51204101301011
654422130415
711450110301
oct2467172653
9811563182
10350025131
1116a642075
1299280a0b
1357694781
14346b6271
1520ae123b
hex14dcf5ab

350025131 has 2 divisors, whose sum is σ = 350025132. Its totient is φ = 350025130.

The previous prime is 350025113. The next prime is 350025139. The reversal of 350025131 is 131520053.

Together with previous prime (350025113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 350025131 - 222 = 345830827 is a prime.

It is a super-2 number, since 2×3500251312 = 245035184663134322, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (350025139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175012565 + 175012566.

It is an arithmetic number, because the mean of its divisors is an integer number (175012566).

Almost surely, 2350025131 is an apocalyptic number.

350025131 is a deficient number, since it is larger than the sum of its proper divisors (1).

350025131 is an equidigital number, since it uses as much as digits as its factorization.

350025131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 450, while the sum is 20.

The square root of 350025131 is about 18708.9585760405. The cubic root of 350025131 is about 704.7467400089.

Adding to 350025131 its reverse (131520053), we get a palindrome (481545184).

The spelling of 350025131 in words is "three hundred fifty million, twenty-five thousand, one hundred thirty-one".