Base | Representation |
---|---|
bin | 1010001011111111000… |
… | …10111001000101011001 |
3 | 1020110111100100100010012 |
4 | 11011333202321011121 |
5 | 21213331221012441 |
6 | 424445204531305 |
7 | 34201060433555 |
oct | 5057742710531 |
9 | 1213440310105 |
10 | 350032204121 |
11 | 1254a2065826 |
12 | 57a090b0b35 |
13 | 27014465912 |
14 | 12d27c56865 |
15 | 9189cb59eb |
hex | 517f8b9159 |
350032204121 has 2 divisors, whose sum is σ = 350032204122. Its totient is φ = 350032204120.
The previous prime is 350032204111. The next prime is 350032204127. The reversal of 350032204121 is 121402230053.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 204996145225 + 145036058896 = 452765^2 + 380836^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-350032204121 is a prime.
It is not a weakly prime, because it can be changed into another prime (350032204127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175016102060 + 175016102061.
It is an arithmetic number, because the mean of its divisors is an integer number (175016102061).
Almost surely, 2350032204121 is an apocalyptic number.
It is an amenable number.
350032204121 is a deficient number, since it is larger than the sum of its proper divisors (1).
350032204121 is an equidigital number, since it uses as much as digits as its factorization.
350032204121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 350032204121 its reverse (121402230053), we get a palindrome (471434434174).
The spelling of 350032204121 in words is "three hundred fifty billion, thirty-two million, two hundred four thousand, one hundred twenty-one".
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