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350042531 is a prime number
BaseRepresentation
bin10100110111010…
…011100110100011
3220101200000002012
4110313103212203
51204102330111
654422343135
711450212106
oct2467234643
9811600065
10350042531
1116a654153
129928aaab
135769c677
14346bc73d
1520ae648b
hex14dd39a3

350042531 has 2 divisors, whose sum is σ = 350042532. Its totient is φ = 350042530.

The previous prime is 350042527. The next prime is 350042573. The reversal of 350042531 is 135240053.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 350042531 - 22 = 350042527 is a prime.

It is a super-2 number, since 2×3500425312 = 245059547017771922, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 350042497 and 350042506.

It is not a weakly prime, because it can be changed into another prime (350042831) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175021265 + 175021266.

It is an arithmetic number, because the mean of its divisors is an integer number (175021266).

Almost surely, 2350042531 is an apocalyptic number.

350042531 is a deficient number, since it is larger than the sum of its proper divisors (1).

350042531 is an equidigital number, since it uses as much as digits as its factorization.

350042531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1800, while the sum is 23.

The square root of 350042531 is about 18709.4235881280. The cubic root of 350042531 is about 704.7584176372.

Adding to 350042531 its reverse (135240053), we get a palindrome (485282584).

The spelling of 350042531 in words is "three hundred fifty million, forty-two thousand, five hundred thirty-one".