Base | Representation |
---|---|
bin | 100000100110011111… |
… | …100010011010100001 |
3 | 10100100121002200101112 |
4 | 200212133202122201 |
5 | 1033142404240001 |
6 | 24025322113105 |
7 | 2346320115635 |
oct | 404637423241 |
9 | 110317080345 |
10 | 35005540001 |
11 | 13933795353 |
12 | 694b34b795 |
13 | 33bb4134a3 |
14 | 19a114cdc5 |
15 | d9d2c6cbb |
hex | 8267e26a1 |
35005540001 has 2 divisors, whose sum is σ = 35005540002. Its totient is φ = 35005540000.
The previous prime is 35005539991. The next prime is 35005540051. The reversal of 35005540001 is 10004550053.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 28476900001 + 6528640000 = 168751^2 + 80800^2 .
It is an emirp because it is prime and its reverse (10004550053) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 35005540001 - 214 = 35005523617 is a prime.
It is a super-2 number, since 2×350055400012 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (35005540051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17502770000 + 17502770001.
It is an arithmetic number, because the mean of its divisors is an integer number (17502770001).
Almost surely, 235005540001 is an apocalyptic number.
It is an amenable number.
35005540001 is a deficient number, since it is larger than the sum of its proper divisors (1).
35005540001 is an equidigital number, since it uses as much as digits as its factorization.
35005540001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1500, while the sum is 23.
The spelling of 35005540001 in words is "thirty-five billion, five million, five hundred forty thousand, one".
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