Base | Representation |
---|---|
bin | 1010001100000001110… |
… | …11111100110001100101 |
3 | 1020110112222021102201100 |
4 | 11012000323330301211 |
5 | 21213403210100203 |
6 | 424451401150313 |
7 | 34201463036526 |
oct | 5060073746145 |
9 | 1213488242640 |
10 | 350055550053 |
11 | 125504260990 |
12 | 57a14a8b399 |
13 | 2701924ac91 |
14 | 12d2adb284d |
15 | 918bd77ea3 |
hex | 5180efcc65 |
350055550053 has 24 divisors (see below), whose sum is σ = 551621266560. Its totient is φ = 212147732160.
The previous prime is 350055550051. The next prime is 350055550063.
350055550053 is a `hidden beast` number, since 3 + 5 + 0 + 0 + 55 + 550 + 0 + 53 = 666.
350055550053 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 350055550053 - 21 = 350055550051 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (350055550051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5536225 + ... + 5599097.
It is an arithmetic number, because the mean of its divisors is an integer number (22984219440).
Almost surely, 2350055550053 is an apocalyptic number.
350055550053 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
350055550053 is a deficient number, since it is larger than the sum of its proper divisors (201565716507).
350055550053 is a wasteful number, since it uses less digits than its factorization.
350055550053 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 119129 (or 119126 counting only the distinct ones).
The product of its (nonzero) digits is 140625, while the sum is 36.
The spelling of 350055550053 in words is "three hundred fifty billion, fifty-five million, five hundred fifty thousand, fifty-three".
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