Base | Representation |
---|---|
bin | 1111111011101000001000… |
… | …10110000111111011110010 |
3 | 11121001020012010202111022101 |
4 | 13331310010112013323302 |
5 | 14042444340003021002 |
6 | 202302241510131014 |
7 | 10244063116152433 |
oct | 775640426077362 |
9 | 147036163674271 |
10 | 35034121142002 |
11 | 10187984057624 |
12 | 3b19a20350a6a |
13 | 167191b623968 |
14 | 89193662748a |
15 | 40b4b7d28587 |
hex | 1fdd04587ef2 |
35034121142002 has 4 divisors (see below), whose sum is σ = 52551181713006. Its totient is φ = 17517060571000.
The previous prime is 35034121141993. The next prime is 35034121142039. The reversal of 35034121142002 is 20024112143053.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 19453030692481 + 15581090449521 = 4410559^2 + 3947289^2 .
It is a super-3 number, since 3×350341211420023 (a number of 42 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8758530285499 + ... + 8758530285502.
Almost surely, 235034121142002 is an apocalyptic number.
35034121142002 is a deficient number, since it is larger than the sum of its proper divisors (17517060571004).
35034121142002 is a wasteful number, since it uses less digits than its factorization.
35034121142002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17517060571003.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 35034121142002 its reverse (20024112143053), we get a palindrome (55058233285055).
The spelling of 35034121142002 in words is "thirty-five trillion, thirty-four billion, one hundred twenty-one million, one hundred forty-two thousand, two".
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