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35034121141993 is a prime number
BaseRepresentation
bin1111111011101000001000…
…10110000111111011101001
311121001020012010202111022001
413331310010112013323221
514042444340003020433
6202302241510131001
710244063116152421
oct775640426077351
9147036163674261
1035034121141993
1110187984057616
123b19a20350a61
13167191b62395c
14891936627481
1540b4b7d2857d
hex1fdd04587ee9

35034121141993 has 2 divisors, whose sum is σ = 35034121141994. Its totient is φ = 35034121141992.

The previous prime is 35034121141951. The next prime is 35034121142039. The reversal of 35034121141993 is 39914112143053.

It is an a-pointer prime, because the next prime (35034121142039) can be obtained adding 35034121141993 to its sum of digits (46).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 34798826296809 + 235294845184 = 5899053^2 + 485072^2 .

It is an emirp because it is prime and its reverse (39914112143053) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-35034121141993 is a prime.

It is not a weakly prime, because it can be changed into another prime (35034121148993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17517060570996 + 17517060570997.

It is an arithmetic number, because the mean of its divisors is an integer number (17517060570997).

Almost surely, 235034121141993 is an apocalyptic number.

It is an amenable number.

35034121141993 is a deficient number, since it is larger than the sum of its proper divisors (1).

35034121141993 is an equidigital number, since it uses as much as digits as its factorization.

35034121141993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 349920, while the sum is 46.

The spelling of 35034121141993 in words is "thirty-five trillion, thirty-four billion, one hundred twenty-one million, one hundred forty-one thousand, nine hundred ninety-three".