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3506412433 is a prime number
BaseRepresentation
bin1101000011111111…
…1001101110010001
3100001100221012121011
43100333321232101
524140120144213
61335534330521
7152615004526
oct32077715621
910040835534
103506412433
11153a307617
1281a359a41
1343b5a3274
1425398b14d
15157c7703d
hexd0ff9b91

3506412433 has 2 divisors, whose sum is σ = 3506412434. Its totient is φ = 3506412432.

The previous prime is 3506412419. The next prime is 3506412443. The reversal of 3506412433 is 3342146053.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1800474624 + 1705937809 = 42432^2 + 41303^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3506412433 is a prime.

It is a super-3 number, since 3×35064124333 (a number of 30 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3506412395 and 3506412404.

It is not a weakly prime, because it can be changed into another prime (3506412443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1753206216 + 1753206217.

It is an arithmetic number, because the mean of its divisors is an integer number (1753206217).

Almost surely, 23506412433 is an apocalyptic number.

It is an amenable number.

3506412433 is a deficient number, since it is larger than the sum of its proper divisors (1).

3506412433 is an equidigital number, since it uses as much as digits as its factorization.

3506412433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25920, while the sum is 31.

The square root of 3506412433 is about 59214.9679810772. The cubic root of 3506412433 is about 1519.2211546884.

Adding to 3506412433 its reverse (3342146053), we get a palindrome (6848558486).

The spelling of 3506412433 in words is "three billion, five hundred six million, four hundred twelve thousand, four hundred thirty-three".