35112133121153 has 4 divisors (see below), whose sum is σ = 38304145223088. Its totient is φ = 31920121019220.

The previous prime is 35112133121113. The next prime is 35112133121173.

It is a happy number.

35112133121153 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 35112133121153 - 2⁴² = 30714086610049 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (35112133121113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1596006050951 + ... + 1596006050972.

It is an arithmetic number, because the mean of its divisors is an integer number (9576036305772).

Almost surely, 2^{35112133121153} is an apocalyptic number.

It is an amenable number.

35112133121153 is a deficient number, since it is larger than the sum of its proper divisors (3192012101935).

35112133121153 is a wasteful number, since it uses less digits than its factorization.

35112133121153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3192012101934.

The product of its digits is 8100, while the sum is 32.

It can be divided in two parts, 3511213 and 3121153, that added together give a palindrome (6632366).

The spelling of 35112133121153 in words is "thirty-five trillion, one hundred twelve billion, one hundred thirty-three million, one hundred twenty-one thousand, one hundred fifty-three".