351134114305153 has 2 divisors, whose sum is σ = 351134114305154. Its totient is φ = 351134114305152.

The previous prime is 351134114305031. The next prime is 351134114305181. The reversal of 351134114305153 is 351503411431153.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 351068873396224 + 65240908929 = 18736832^2 + 255423^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-351134114305153 is a prime.

It is not a weakly prime, because it can be changed into another prime (351134114305753) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175567057152576 + 175567057152577.

It is an arithmetic number, because the mean of its divisors is an integer number (175567057152577).

Almost surely, 2^{351134114305153} is an apocalyptic number.

It is an amenable number.

351134114305153 is a deficient number, since it is larger than the sum of its proper divisors (1).

351134114305153 is an equidigital number, since it uses as much as digits as its factorization.

351134114305153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162000, while the sum is 40.

The spelling of 351134114305153 in words is "three hundred fifty-one trillion, one hundred thirty-four billion, one hundred fourteen million, three hundred five thousand, one hundred fifty-three".