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351151530242 = 2175575765121
BaseRepresentation
bin1010001110000100100…
…00110010000100000010
31020120101100112222220012
411013002100302010002
521223124242431432
6425152231544522
734240601521202
oct5070220620402
91216340488805
10351151530242
11125a16980037
125807bb2b142
1327162322076
1412dd2786402
1592031b7cb2
hex51c2432102

351151530242 has 4 divisors (see below), whose sum is σ = 526727295366. Its totient is φ = 175575765120.

The previous prime is 351151530181. The next prime is 351151530259. The reversal of 351151530242 is 242035151153.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 242035151153 = 2411004295233.

It can be written as a sum of positive squares in only one way, i.e., 285958632001 + 65192898241 = 534751^2 + 255329^2 .

It is a junction number, because it is equal to n+sod(n) for n = 351151530199 and 351151530208.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 87787882559 + ... + 87787882562.

Almost surely, 2351151530242 is an apocalyptic number.

351151530242 is a deficient number, since it is larger than the sum of its proper divisors (175575765124).

351151530242 is a wasteful number, since it uses less digits than its factorization.

351151530242 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 175575765123.

The product of its (nonzero) digits is 18000, while the sum is 32.

Adding to 351151530242 its reverse (242035151153), we get a palindrome (593186681395).

The spelling of 351151530242 in words is "three hundred fifty-one billion, one hundred fifty-one million, five hundred thirty thousand, two hundred forty-two".

Divisors: 1 2 175575765121 351151530242