351204315133151 has 4 divisors (see below), whose sum is σ = 351204352676304. Its totient is φ = 351204277590000.

The previous prime is 351204315133099. The next prime is 351204315133169. The reversal of 351204315133151 is 151331513402153.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-351204315133151 is a prime.

It is a super-3 number, since 3×351204315133151³ (a number of 45 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (351204315133751) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7764851 + ... + 27617051.

It is an arithmetic number, because the mean of its divisors is an integer number (87801088169076).

Almost surely, 2^{351204315133151} is an apocalyptic number.

351204315133151 is a deficient number, since it is larger than the sum of its proper divisors (37543153).

351204315133151 is a wasteful number, since it uses less digits than its factorization.

351204315133151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37543152.

The product of its (nonzero) digits is 81000, while the sum is 38.

The spelling of 351204315133151 in words is "three hundred fifty-one trillion, two hundred four billion, three hundred fifteen million, one hundred thirty-three thousand, one hundred fifty-one".