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3512149085041 is a prime number
BaseRepresentation
bin110011000110111100011…
…001100000101101110001
3110102202110201010110021021
4303012330121200231301
5430020340131210131
611245243051455441
7511513220436442
oct63067431405561
913382421113237
103512149085041
111134548662623
12488817757581
131c626a980a9c
14c1dbb8652c9
156155bc45e11
hex331bc660b71

3512149085041 has 2 divisors, whose sum is σ = 3512149085042. Its totient is φ = 3512149085040.

The previous prime is 3512149085021. The next prime is 3512149085047. The reversal of 3512149085041 is 1405809412153.

3512149085041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2411110200625 + 1101038884416 = 1552775^2 + 1049304^2 .

It is an emirp because it is prime and its reverse (1405809412153) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3512149085041 is a prime.

It is not a weakly prime, because it can be changed into another prime (3512149085047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1756074542520 + 1756074542521.

It is an arithmetic number, because the mean of its divisors is an integer number (1756074542521).

Almost surely, 23512149085041 is an apocalyptic number.

It is an amenable number.

3512149085041 is a deficient number, since it is larger than the sum of its proper divisors (1).

3512149085041 is an equidigital number, since it uses as much as digits as its factorization.

3512149085041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 172800, while the sum is 43.

The spelling of 3512149085041 in words is "three trillion, five hundred twelve billion, one hundred forty-nine million, eighty-five thousand, forty-one".