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35130004843 is a prime number
BaseRepresentation
bin100000101101111010…
…010101010101101011
310100200021022011001111
4200231322111111223
51033421240123333
624045525531151
72352361054123
oct405572252553
9110607264044
1035130004843
1113997a7665a
126984b73ab7
13340b14171b
1419b38abc83
15da91b04cd
hex82de9556b

35130004843 has 2 divisors, whose sum is σ = 35130004844. Its totient is φ = 35130004842.

The previous prime is 35130004831. The next prime is 35130005047. The reversal of 35130004843 is 34840003153.

It is a weak prime.

It is an emirp because it is prime and its reverse (34840003153) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 35130004843 - 213 = 35129996651 is a prime.

It is not a weakly prime, because it can be changed into another prime (35130004813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17565002421 + 17565002422.

It is an arithmetic number, because the mean of its divisors is an integer number (17565002422).

Almost surely, 235130004843 is an apocalyptic number.

35130004843 is a deficient number, since it is larger than the sum of its proper divisors (1).

35130004843 is an equidigital number, since it uses as much as digits as its factorization.

35130004843 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 35130004843 its reverse (34840003153), we get a palindrome (69970007996).

The spelling of 35130004843 in words is "thirty-five billion, one hundred thirty million, four thousand, eight hundred forty-three".