35135124343 has 4 divisors (see below), whose sum is σ = 38329226568. Its totient is φ = 31941022120.

The previous prime is 35135124341. The next prime is 35135124359. The reversal of 35135124343 is 34342153153.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 35135124343 - 2¹ = 35135124341 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 35135124299 and 35135124308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (35135124341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1597051096 + ... + 1597051117.

It is an arithmetic number, because the mean of its divisors is an integer number (9582306642).

Almost surely, 2^35135124343 is an apocalyptic number.

35135124343 is a deficient number, since it is larger than the sum of its proper divisors (3194102225).

35135124343 is a wasteful number, since it uses less digits than its factorization.

35135124343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3194102224.

The product of its digits is 64800, while the sum is 34.

Adding to 35135124343 its reverse (34342153153), we get a palindrome (69477277496).

The spelling of 35135124343 in words is "thirty-five billion, one hundred thirty-five million, one hundred twenty-four thousand, three hundred forty-three".