Base | Representation |
---|---|
bin | 100000101110100000… |
… | …101000001001000011 |
3 | 10100200222012011021100 |
4 | 200232200220021003 |
5 | 1033431322341311 |
6 | 24050525025443 |
7 | 2352542303631 |
oct | 405640501103 |
9 | 110628164240 |
10 | 35140043331 |
11 | 139a2702728 |
12 | 69883b5283 |
13 | 3410247963 |
14 | 19b4d62351 |
15 | da9ee4a56 |
hex | 82e828243 |
35140043331 has 24 divisors (see below), whose sum is σ = 51006752784. Its totient is φ = 23311918080.
The previous prime is 35140043327. The next prime is 35140043339. The reversal of 35140043331 is 13334004153.
It is not a de Polignac number, because 35140043331 - 22 = 35140043327 is a prime.
It is a super-2 number, since 2×351400433312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 35140043295 and 35140043304.
It is not an unprimeable number, because it can be changed into a prime (35140043339) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6651411 + ... + 6656691.
It is an arithmetic number, because the mean of its divisors is an integer number (2125281366).
Almost surely, 235140043331 is an apocalyptic number.
35140043331 is a deficient number, since it is larger than the sum of its proper divisors (15866709453).
35140043331 is a wasteful number, since it uses less digits than its factorization.
35140043331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8771 (or 8768 counting only the distinct ones).
The product of its (nonzero) digits is 6480, while the sum is 27.
Adding to 35140043331 its reverse (13334004153), we get a palindrome (48474047484).
The spelling of 35140043331 in words is "thirty-five billion, one hundred forty million, forty-three thousand, three hundred thirty-one".
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