Base | Representation |
---|---|
bin | 1010001110100101001… |
… | …00011111101110101001 |
3 | 1020121002102101110222111 |
4 | 11013102210133232221 |
5 | 21224204313232411 |
6 | 425235324122321 |
7 | 34250433230242 |
oct | 5072244375651 |
9 | 1217072343874 |
10 | 351425133481 |
11 | 126047365214 |
12 | 581376963a1 |
13 | 271a6c09c86 |
14 | 1301ac47cc9 |
15 | 921c210721 |
hex | 51d291fba9 |
351425133481 has 2 divisors, whose sum is σ = 351425133482. Its totient is φ = 351425133480.
The previous prime is 351425133473. The next prime is 351425133487. The reversal of 351425133481 is 184331524153.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 229268592400 + 122156541081 = 478820^2 + 349509^2 .
It is a cyclic number.
It is not a de Polignac number, because 351425133481 - 23 = 351425133473 is a prime.
It is a super-2 number, since 2×3514251334812 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (351425133487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175712566740 + 175712566741.
It is an arithmetic number, because the mean of its divisors is an integer number (175712566741).
Almost surely, 2351425133481 is an apocalyptic number.
It is an amenable number.
351425133481 is a deficient number, since it is larger than the sum of its proper divisors (1).
351425133481 is an equidigital number, since it uses as much as digits as its factorization.
351425133481 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 172800, while the sum is 40.
The spelling of 351425133481 in words is "three hundred fifty-one billion, four hundred twenty-five million, one hundred thirty-three thousand, four hundred eighty-one".
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