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351542424113 is a prime number
BaseRepresentation
bin1010001110110011000…
…11111011001000110001
31020121101121002110110222
411013121203323020301
521224424330032423
6425255114102425
734253356205366
oct5073143731061
91217347073428
10351542424113
111260a7596421
125816aa1aa15
13271c52c590a
141302c65a46d
15922767d3c8
hex51d98fb231

351542424113 has 2 divisors, whose sum is σ = 351542424114. Its totient is φ = 351542424112.

The previous prime is 351542424049. The next prime is 351542424139. The reversal of 351542424113 is 311424245153.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 291089383729 + 60453040384 = 539527^2 + 245872^2 .

It is a cyclic number.

It is not a de Polignac number, because 351542424113 - 26 = 351542424049 is a prime.

It is a super-3 number, since 3×3515424241133 (a number of 36 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (351542424143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175771212056 + 175771212057.

It is an arithmetic number, because the mean of its divisors is an integer number (175771212057).

Almost surely, 2351542424113 is an apocalyptic number.

It is an amenable number.

351542424113 is a deficient number, since it is larger than the sum of its proper divisors (1).

351542424113 is an equidigital number, since it uses as much as digits as its factorization.

351542424113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 57600, while the sum is 35.

Adding to 351542424113 its reverse (311424245153), we get a palindrome (662966669266).

The spelling of 351542424113 in words is "three hundred fifty-one billion, five hundred forty-two million, four hundred twenty-four thousand, one hundred thirteen".