Base | Representation |
---|---|
bin | 110011001010100010100… |
… | …001110011110100010001 |
3 | 110110010102210011021111112 |
4 | 303022202201303310101 |
5 | 430101242031120423 |
6 | 11251122133023105 |
7 | 512011002026063 |
oct | 63124241636421 |
9 | 13403383137445 |
10 | 3516010020113 |
11 | 1136149aa3258 |
12 | 489514784a95 |
13 | 1c6734831956 |
14 | c2266539733 |
15 | 616d5b9ba78 |
hex | 332a2873d11 |
3516010020113 has 2 divisors, whose sum is σ = 3516010020114. Its totient is φ = 3516010020112.
The previous prime is 3516010020091. The next prime is 3516010020121. The reversal of 3516010020113 is 3110200106153.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3279514549249 + 236495470864 = 1810943^2 + 486308^2 .
It is a cyclic number.
It is not a de Polignac number, because 3516010020113 - 212 = 3516010016017 is a prime.
It is not a weakly prime, because it can be changed into another prime (3516010020143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1758005010056 + 1758005010057.
It is an arithmetic number, because the mean of its divisors is an integer number (1758005010057).
Almost surely, 23516010020113 is an apocalyptic number.
It is an amenable number.
3516010020113 is a deficient number, since it is larger than the sum of its proper divisors (1).
3516010020113 is an equidigital number, since it uses as much as digits as its factorization.
3516010020113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 3516010020113 its reverse (3110200106153), we get a palindrome (6626210126266).
The spelling of 3516010020113 in words is "three trillion, five hundred sixteen billion, ten million, twenty thousand, one hundred thirteen".
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