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35312340215443 is a prime number
BaseRepresentation
bin10000000011101110010110…
…11111101010011010010011
311122000211022201000210211211
420001313023133222122103
514112024133043343233
6203034133134320551
710303142465233354
oct1001671337523223
9148024281023754
1035312340215443
1110284974508375
123b63927359157
131691c29b05335
148a11aab33d2b
1541384d22e5cd
hex201dcb7ea693

35312340215443 has 2 divisors, whose sum is σ = 35312340215444. Its totient is φ = 35312340215442.

The previous prime is 35312340215429. The next prime is 35312340215491. The reversal of 35312340215443 is 34451204321353.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-35312340215443 is a prime.

It is a super-2 number, since 2×353123402154432 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 35312340215396 and 35312340215405.

It is not a weakly prime, because it can be changed into another prime (35312340215413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17656170107721 + 17656170107722.

It is an arithmetic number, because the mean of its divisors is an integer number (17656170107722).

Almost surely, 235312340215443 is an apocalyptic number.

35312340215443 is a deficient number, since it is larger than the sum of its proper divisors (1).

35312340215443 is an equidigital number, since it uses as much as digits as its factorization.

35312340215443 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 518400, while the sum is 40.

Adding to 35312340215443 its reverse (34451204321353), we get a palindrome (69763544536796).

The spelling of 35312340215443 in words is "thirty-five trillion, three hundred twelve billion, three hundred forty million, two hundred fifteen thousand, four hundred forty-three".