Base | Representation |
---|---|
bin | 110011011000111001001… |
… | …101110100001010000011 |
3 | 110111121012221110211010210 |
4 | 303120321031310022003 |
5 | 430324323244241011 |
6 | 11302151403325203 |
7 | 513064645365360 |
oct | 63307115641203 |
9 | 13447187424123 |
10 | 3531423040131 |
11 | 1141739273328 |
12 | 4904b6520803 |
13 | 1c801caca63c |
14 | c2cc9553467 |
15 | 61cd8d976a6 |
hex | 33639374283 |
3531423040131 has 16 divisors (see below), whose sum is σ = 5415491327744. Its totient is φ = 2005102797984.
The previous prime is 3531423040087. The next prime is 3531423040133. The reversal of 3531423040131 is 1310403241353.
It is a happy number.
It is not a de Polignac number, because 3531423040131 - 219 = 3531422515843 is a prime.
It is a super-2 number, since 2×35314230401312 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3531423040133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 535547665 + ... + 535554258.
It is an arithmetic number, because the mean of its divisors is an integer number (338468207984).
Almost surely, 23531423040131 is an apocalyptic number.
3531423040131 is a deficient number, since it is larger than the sum of its proper divisors (1884068287613).
3531423040131 is a wasteful number, since it uses less digits than its factorization.
3531423040131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1071102090.
The product of its (nonzero) digits is 12960, while the sum is 30.
Adding to 3531423040131 its reverse (1310403241353), we get a palindrome (4841826281484).
The spelling of 3531423040131 in words is "three trillion, five hundred thirty-one billion, four hundred twenty-three million, forty thousand, one hundred thirty-one".
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