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35340412531 is a prime number
BaseRepresentation
bin100000111010011100…
…111110011001110011
310101012221012222010211
4200322130332121303
51034334121200111
624122443404551
72360524356454
oct407234763163
9111187188124
1035340412531
1113a95818006
126a23523757
133442901008
1419d37dd12b
15dbc8c3521
hex83a73e673

35340412531 has 2 divisors, whose sum is σ = 35340412532. Its totient is φ = 35340412530.

The previous prime is 35340412501. The next prime is 35340412553. The reversal of 35340412531 is 13521404353.

It is a strong prime.

It is an emirp because it is prime and its reverse (13521404353) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 35340412531 - 221 = 35338315379 is a prime.

It is a super-2 number, since 2×353404125312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 35340412493 and 35340412502.

It is not a weakly prime, because it can be changed into another prime (35340412501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17670206265 + 17670206266.

It is an arithmetic number, because the mean of its divisors is an integer number (17670206266).

Almost surely, 235340412531 is an apocalyptic number.

35340412531 is a deficient number, since it is larger than the sum of its proper divisors (1).

35340412531 is an equidigital number, since it uses as much as digits as its factorization.

35340412531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 35340412531 its reverse (13521404353), we get a palindrome (48861816884).

The spelling of 35340412531 in words is "thirty-five billion, three hundred forty million, four hundred twelve thousand, five hundred thirty-one".