3534046433 has 2 divisors, whose sum is σ = 3534046434. Its totient is φ = 3534046432.

The previous prime is 3534046427. The next prime is 3534046447. The reversal of 3534046433 is 3346404353.

3534046433 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2701608529 + 832437904 = 51977^2 + 28852^2 .

It is an emirp because it is prime and its reverse (3346404353) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3534046433 - 2¹⁰ = 3534045409 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3534046393 and 3534046402.

It is not a weakly prime, because it can be changed into another prime (3534046403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1767023216 + 1767023217.

It is an arithmetic number, because the mean of its divisors is an integer number (1767023217).

Almost surely, 2^3534046433 is an apocalyptic number.

It is an amenable number.

3534046433 is a deficient number, since it is larger than the sum of its proper divisors (1).

3534046433 is an equidigital number, since it uses as much as digits as its factorization.

3534046433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 155520, while the sum is 35.

The square root of 3534046433 is about 59447.8463276846. The cubic root of 3534046433 is about 1523.2017047574.

The spelling of 3534046433 in words is "three billion, five hundred thirty-four million, forty-six thousand, four hundred thirty-three".