Base | Representation |
---|---|
bin | 100000111011000001… |
… | …100110011000000001 |
3 | 10101020121021202010002 |
4 | 200323001212120001 |
5 | 1034344100412231 |
6 | 24123425245345 |
7 | 2361002104451 |
oct | 407301463001 |
9 | 111217252102 |
10 | 35350013441 |
11 | 13aa0185346 |
12 | 6a26793855 |
13 | 34448b3022 |
14 | 19d4bbbd61 |
15 | dbd66d0cb |
hex | 83b066601 |
35350013441 has 2 divisors, whose sum is σ = 35350013442. Its totient is φ = 35350013440.
The previous prime is 35350013431. The next prime is 35350013471. The reversal of 35350013441 is 14431005353.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 29447932816 + 5902080625 = 171604^2 + 76825^2 .
It is an emirp because it is prime and its reverse (14431005353) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-35350013441 is a prime.
It is not a weakly prime, because it can be changed into another prime (35350013431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17675006720 + 17675006721.
It is an arithmetic number, because the mean of its divisors is an integer number (17675006721).
Almost surely, 235350013441 is an apocalyptic number.
It is an amenable number.
35350013441 is a deficient number, since it is larger than the sum of its proper divisors (1).
35350013441 is an equidigital number, since it uses as much as digits as its factorization.
35350013441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10800, while the sum is 29.
Adding to 35350013441 its reverse (14431005353), we get a palindrome (49781018794).
The spelling of 35350013441 in words is "thirty-five billion, three hundred fifty million, thirteen thousand, four hundred forty-one".
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