Base | Representation |
---|---|
bin | 100000111101111000… |
… | …101000001111000001 |
3 | 10101100221120101020221 |
4 | 200331320220033001 |
5 | 1034443341242114 |
6 | 24132301503041 |
7 | 2362123656652 |
oct | 407570501701 |
9 | 111327511227 |
10 | 35397993409 |
11 | 14015276409 |
12 | 6a3a871a81 |
13 | 3451811b3c |
14 | 19db30b529 |
15 | dc2999524 |
hex | 83de283c1 |
35397993409 has 2 divisors, whose sum is σ = 35397993410. Its totient is φ = 35397993408.
The previous prime is 35397993403. The next prime is 35397993451. The reversal of 35397993409 is 90439979353.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 18037295809 + 17360697600 = 134303^2 + 131760^2 .
It is an emirp because it is prime and its reverse (90439979353) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 35397993409 - 211 = 35397991361 is a prime.
It is a super-3 number, since 3×353979934093 (a number of 33 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (35397993403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17698996704 + 17698996705.
It is an arithmetic number, because the mean of its divisors is an integer number (17698996705).
Almost surely, 235397993409 is an apocalyptic number.
It is an amenable number.
35397993409 is a deficient number, since it is larger than the sum of its proper divisors (1).
35397993409 is an equidigital number, since it uses as much as digits as its factorization.
35397993409 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24800580, while the sum is 61.
The spelling of 35397993409 in words is "thirty-five billion, three hundred ninety-seven million, nine hundred ninety-three thousand, four hundred nine".
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