354020131 has 2 divisors, whose sum is σ = 354020132. Its totient is φ = 354020130.

The previous prime is 354020123. The next prime is 354020203. The reversal of 354020131 is 131020453.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 354020131 - 2³ = 354020123 is a prime.

It is a super-2 number, since 2×354020131² = 250660506306514322, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 354020099 and 354020108.

It is not a weakly prime, because it can be changed into another prime (354020101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177010065 + 177010066.

It is an arithmetic number, because the mean of its divisors is an integer number (177010066).

Almost surely, 2^354020131 is an apocalyptic number.

354020131 is a deficient number, since it is larger than the sum of its proper divisors (1).

354020131 is an equidigital number, since it uses as much as digits as its factorization.

354020131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 360, while the sum is 19.

The square root of 354020131 is about 18815.4226899105. The cubic root of 354020131 is about 707.4178046329.

Adding to 354020131 its reverse (131020453), we get a palindrome (485040584).

The spelling of 354020131 in words is "three hundred fifty-four million, twenty thousand, one hundred thirty-one".