3540313115013 has 4 divisors (see below), whose sum is σ = 4720417486688. Its totient is φ = 2360208743340.

The previous prime is 3540313114997. The next prime is 3540313115021. The reversal of 3540313115013 is 3105113130453.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 3540313115013 - 2⁴ = 3540313114997 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3540313115093) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 590052185833 + ... + 590052185838.

It is an arithmetic number, because the mean of its divisors is an integer number (1180104371672).

Almost surely, 2^{3540313115013} is an apocalyptic number.

It is an amenable number.

3540313115013 is a deficient number, since it is larger than the sum of its proper divisors (1180104371675).

3540313115013 is a wasteful number, since it uses less digits than its factorization.

3540313115013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1180104371674.

The product of its (nonzero) digits is 8100, while the sum is 30.

Adding to 3540313115013 its reverse (3105113130453), we get a palindrome (6645426245466).

The spelling of 3540313115013 in words is "three trillion, five hundred forty billion, three hundred thirteen million, one hundred fifteen thousand, thirteen".