Base | Representation |
---|---|
bin | 101000010000000001001101… |
… | …1000010000001000010111011 |
3 | 1201102120101220211200101022221 |
4 | 1100200002123002001002323 |
5 | 332401134331324002143 |
6 | 3252554104115224511 |
7 | 134400634462441342 |
oct | 12040023302010273 |
9 | 1642511824611287 |
10 | 354045345140923 |
11 | a289a873430757 |
12 | 338604398a8137 |
13 | 122724431a8c47 |
14 | 635dc597b2b59 |
15 | 2ade7ea3412ed |
hex | 142009b0810bb |
354045345140923 has 2 divisors, whose sum is σ = 354045345140924. Its totient is φ = 354045345140922.
The previous prime is 354045345140899. The next prime is 354045345141029. The reversal of 354045345140923 is 329041543540453.
It is a weak prime.
It is an emirp because it is prime and its reverse (329041543540453) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 354045345140923 - 233 = 354036755206331 is a prime.
It is not a weakly prime, because it can be changed into another prime (354045345140323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177022672570461 + 177022672570462.
It is an arithmetic number, because the mean of its divisors is an integer number (177022672570462).
Almost surely, 2354045345140923 is an apocalyptic number.
354045345140923 is a deficient number, since it is larger than the sum of its proper divisors (1).
354045345140923 is an equidigital number, since it uses as much as digits as its factorization.
354045345140923 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552000, while the sum is 52.
The spelling of 354045345140923 in words is "three hundred fifty-four trillion, forty-five billion, three hundred forty-five million, one hundred forty thousand, nine hundred twenty-three".
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