3540750410501 has 4 divisors (see below), whose sum is σ = 3550895827500. Its totient is φ = 3530604993504.

The previous prime is 3540750410467. The next prime is 3540750410543. The reversal of 3540750410501 is 1050140570453.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1055240508001 + 2485509902500 = 1027249^2 + 1576550^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3540750410501 is a prime.

It is a super-4 number, since 4×3540750410501⁴ (a number of 51 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3540750412501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5072707976 + ... + 5072708673.

It is an arithmetic number, because the mean of its divisors is an integer number (887723956875).

Almost surely, 2^{3540750410501} is an apocalyptic number.

It is an amenable number.

3540750410501 is a deficient number, since it is larger than the sum of its proper divisors (10145416999).

3540750410501 is a wasteful number, since it uses less digits than its factorization.

3540750410501 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10145416998.

The product of its (nonzero) digits is 42000, while the sum is 35.

Adding to 3540750410501 its reverse (1050140570453), we get a palindrome (4590890980954).

The spelling of 3540750410501 in words is "three trillion, five hundred forty billion, seven hundred fifty million, four hundred ten thousand, five hundred one".