Base | Representation |
---|---|
bin | 110011100001110110100… |
… | …111100011011001100001 |
3 | 110112112001101101010021200 |
4 | 303201312213203121201 |
5 | 431004024020211001 |
6 | 11310422135311413 |
7 | 513555230666424 |
oct | 63416647433141 |
9 | 13475041333250 |
10 | 3541043132001 |
11 | 1145825595781 |
12 | 49234021b569 |
13 | 1c8bc3b8c6ab |
14 | c355d0619bb |
15 | 6219d710086 |
hex | 338769e3661 |
3541043132001 has 24 divisors (see below), whose sum is σ = 5152824431040. Its totient is φ = 2343228997536.
The previous prime is 3541043131999. The next prime is 3541043132009. The reversal of 3541043132001 is 1002313401453.
It is a happy number.
3541043132001 is a `hidden beast` number, since 3 + 5 + 410 + 43 + 1 + 3 + 200 + 1 = 666.
It is not a de Polignac number, because 3541043132001 - 21 = 3541043131999 is a prime.
It is not an unprimeable number, because it can be changed into a prime (3541043132009) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2044711 + ... + 3356028.
It is an arithmetic number, because the mean of its divisors is an integer number (214701017960).
Almost surely, 23541043132001 is an apocalyptic number.
It is an amenable number.
3541043132001 is a deficient number, since it is larger than the sum of its proper divisors (1611781299039).
3541043132001 is a wasteful number, since it uses less digits than its factorization.
3541043132001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5401285 (or 5401282 counting only the distinct ones).
The product of its (nonzero) digits is 4320, while the sum is 27.
Adding to 3541043132001 its reverse (1002313401453), we get a palindrome (4543356533454).
The spelling of 3541043132001 in words is "three trillion, five hundred forty-one billion, forty-three million, one hundred thirty-two thousand, one".
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