Base | Representation |
---|---|
bin | 100000111111001101… |
… | …001000011011111011 |
3 | 10101102111020211002011 |
4 | 200333031020123323 |
5 | 1040020024123103 |
6 | 24134412350351 |
7 | 2362513161016 |
oct | 407715103373 |
9 | 111374224064 |
10 | 35420145403 |
11 | 14026826545 |
12 | 6a461753b7 |
13 | 3456299926 |
14 | 1a0023637d |
15 | dc48c2d6d |
hex | 83f3486fb |
35420145403 has 2 divisors, whose sum is σ = 35420145404. Its totient is φ = 35420145402.
The previous prime is 35420145389. The next prime is 35420145413. The reversal of 35420145403 is 30454102453.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 35420145403 - 225 = 35386590971 is a prime.
It is a super-3 number, since 3×354201454033 (a number of 33 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (35420145413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17710072701 + 17710072702.
It is an arithmetic number, because the mean of its divisors is an integer number (17710072702).
Almost surely, 235420145403 is an apocalyptic number.
35420145403 is a deficient number, since it is larger than the sum of its proper divisors (1).
35420145403 is an equidigital number, since it uses as much as digits as its factorization.
35420145403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28800, while the sum is 31.
Adding to 35420145403 its reverse (30454102453), we get a palindrome (65874247856).
The spelling of 35420145403 in words is "thirty-five billion, four hundred twenty million, one hundred forty-five thousand, four hundred three".
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