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35420145403 is a prime number
BaseRepresentation
bin100000111111001101…
…001000011011111011
310101102111020211002011
4200333031020123323
51040020024123103
624134412350351
72362513161016
oct407715103373
9111374224064
1035420145403
1114026826545
126a461753b7
133456299926
141a0023637d
15dc48c2d6d
hex83f3486fb

35420145403 has 2 divisors, whose sum is σ = 35420145404. Its totient is φ = 35420145402.

The previous prime is 35420145389. The next prime is 35420145413. The reversal of 35420145403 is 30454102453.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 35420145403 - 225 = 35386590971 is a prime.

It is a super-3 number, since 3×354201454033 (a number of 33 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (35420145413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17710072701 + 17710072702.

It is an arithmetic number, because the mean of its divisors is an integer number (17710072702).

Almost surely, 235420145403 is an apocalyptic number.

35420145403 is a deficient number, since it is larger than the sum of its proper divisors (1).

35420145403 is an equidigital number, since it uses as much as digits as its factorization.

35420145403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28800, while the sum is 31.

Adding to 35420145403 its reverse (30454102453), we get a palindrome (65874247856).

The spelling of 35420145403 in words is "thirty-five billion, four hundred twenty million, one hundred forty-five thousand, four hundred three".