Base | Representation |
---|---|
bin | 100000111111001110… |
… | …010001010111010011 |
3 | 10101102111210222211120 |
4 | 200333032101113103 |
5 | 1040020113202430 |
6 | 24134423013323 |
7 | 2362515543630 |
oct | 407716212723 |
9 | 111374728746 |
10 | 35420444115 |
11 | 14026a0aa11 |
12 | 6a4629a243 |
13 | 3456372894 |
14 | 1a002b3187 |
15 | dc4931610 |
hex | 83f3915d3 |
35420444115 has 32 divisors (see below), whose sum is σ = 65735523840. Its totient is φ = 15950525184.
The previous prime is 35420444113. The next prime is 35420444131. The reversal of 35420444115 is 51144402453.
It is a happy number.
It is not a de Polignac number, because 35420444115 - 21 = 35420444113 is a prime.
It is a super-3 number, since 3×354204441153 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (35420444113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2510410 + ... + 2524479.
It is an arithmetic number, because the mean of its divisors is an integer number (2054235120).
Almost surely, 235420444115 is an apocalyptic number.
35420444115 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
35420444115 is a deficient number, since it is larger than the sum of its proper divisors (30315079725).
35420444115 is a wasteful number, since it uses less digits than its factorization.
35420444115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5034971.
The product of its (nonzero) digits is 38400, while the sum is 33.
Adding to 35420444115 its reverse (51144402453), we get a palindrome (86564846568).
The spelling of 35420444115 in words is "thirty-five billion, four hundred twenty million, four hundred forty-four thousand, one hundred fifteen".
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