Base | Representation |
---|---|
bin | 100000111111010001… |
… | …101000100001111011 |
3 | 10101102120110202210001 |
4 | 200333101220201323 |
5 | 1040020324403220 |
6 | 24134453533431 |
7 | 2362526204236 |
oct | 407721504173 |
9 | 111376422701 |
10 | 35421325435 |
11 | 14027462081 |
12 | 6a46644277 |
13 | 34565c0a82 |
14 | 1a0046241d |
15 | dc4a5780a |
hex | 83f46887b |
35421325435 has 32 divisors (see below), whose sum is σ = 45077394240. Its totient is φ = 26678066688.
The previous prime is 35421325427. The next prime is 35421325463. The reversal of 35421325435 is 53452312453.
35421325435 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 35421325435 - 23 = 35421325427 is a prime.
It is a super-3 number, since 3×354213254353 (a number of 33 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 35421325394 and 35421325403.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1238517 + ... + 1266793.
It is an arithmetic number, because the mean of its divisors is an integer number (1408668570).
Almost surely, 235421325435 is an apocalyptic number.
35421325435 is a deficient number, since it is larger than the sum of its proper divisors (9656068805).
35421325435 is a wasteful number, since it uses less digits than its factorization.
35421325435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28527.
The product of its digits is 216000, while the sum is 37.
Adding to 35421325435 its reverse (53452312453), we get a palindrome (88873637888).
The spelling of 35421325435 in words is "thirty-five billion, four hundred twenty-one million, three hundred twenty-five thousand, four hundred thirty-five".
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