Base | Representation |
---|---|
bin | 100000111111010001… |
… | …111101110001100101 |
3 | 10101102120122012010221 |
4 | 200333101331301211 |
5 | 1040020340144303 |
6 | 24134455444341 |
7 | 2362530016030 |
oct | 407721756145 |
9 | 111376565127 |
10 | 35421412453 |
11 | 14027511499 |
12 | 6a466866b1 |
13 | 345662156b |
14 | 1a00486017 |
15 | dc4a734bd |
hex | 83f47dc65 |
35421412453 has 16 divisors (see below), whose sum is σ = 42426190080. Its totient is φ = 28914310656.
The previous prime is 35421412447. The next prime is 35421412459.
35421412453 is nontrivially palindromic in base 10.
It is an interprime number because it is at equal distance from previous prime (35421412447) and next prime (35421412459).
It is not a de Polignac number, because 35421412453 - 25 = 35421412421 is a prime.
It is a super-3 number, since 3×354214124533 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (35421412459) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 443500 + ... + 517237.
It is an arithmetic number, because the mean of its divisors is an integer number (2651636880).
Almost surely, 235421412453 is an apocalyptic number.
It is an amenable number.
35421412453 is a deficient number, since it is larger than the sum of its proper divisors (7004777627).
35421412453 is a wasteful number, since it uses less digits than its factorization.
35421412453 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 960996.
The product of its digits is 57600, while the sum is 34.
The spelling of 35421412453 in words is "thirty-five billion, four hundred twenty-one million, four hundred twelve thousand, four hundred fifty-three".
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