3542310132453 has 12 divisors (see below), whose sum is σ = 5293107094860. Its totient is φ = 2280107671296.

The previous prime is 3542310132451. The next prime is 3542310132463.

3542310132453 is a `hidden beast` number, since 3 + 5 + 42 + 31 + 0 + 132 + 453 = 666.

3542310132453 is nontrivially palindromic in base 10.

It can be written as a sum of positive squares in 2 ways, for example, as 2638473938244 + 903836194209 = 1624338^2 + 950703^2 .

It is not a de Polignac number, because 3542310132453 - 2¹ = 3542310132451 is a prime.

It is a super-3 number, since 3×3542310132453³ (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3542310132451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6786034476 + ... + 6786034997.

It is an arithmetic number, because the mean of its divisors is an integer number (441092257905).

Almost surely, 2^{3542310132453} is an apocalyptic number.

It is an amenable number.

3542310132453 is a deficient number, since it is larger than the sum of its proper divisors (1750796962407).

3542310132453 is a wasteful number, since it uses less digits than its factorization.

3542310132453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13572069508 (or 13572069505 counting only the distinct ones).

The product of its (nonzero) digits is 129600, while the sum is 36.

It can be divided in two parts, 3542310 and 132453, that added together give a palindrome (3674763).

The spelling of 3542310132453 in words is "three trillion, five hundred forty-two billion, three hundred ten million, one hundred thirty-two thousand, four hundred fifty-three".