Base | Representation |
---|---|
bin | 101000010001010111101011… |
… | …0111110110010001001000110 |
3 | 1201110020011012212000012122011 |
4 | 1100202233112332302021012 |
5 | 332412210124314121014 |
6 | 3253215253555124434 |
7 | 134420230154224012 |
oct | 12042572676621106 |
9 | 1643204185005564 |
10 | 354231034520134 |
11 | a29615a1225722 |
12 | 338904208a371a |
13 | 12286ac6740165 |
14 | 6368c33041542 |
15 | 2ae45672767c4 |
hex | 1422bd6fb2246 |
354231034520134 has 8 divisors (see below), whose sum is σ = 531376250931288. Its totient is φ = 177105617543040.
The previous prime is 354231034520059. The next prime is 354231034520147. The reversal of 354231034520134 is 431025430132453.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×3542310345201343 (a number of 45 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4949813787 + ... + 4949885350.
It is an arithmetic number, because the mean of its divisors is an integer number (66422031366411).
Almost surely, 2354231034520134 is an apocalyptic number.
354231034520134 is a deficient number, since it is larger than the sum of its proper divisors (177145216411154).
354231034520134 is a wasteful number, since it uses less digits than its factorization.
354231034520134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9899717030.
The product of its (nonzero) digits is 518400, while the sum is 40.
Adding to 354231034520134 its reverse (431025430132453), we get a palindrome (785256464652587).
The spelling of 354231034520134 in words is "three hundred fifty-four trillion, two hundred thirty-one billion, thirty-four million, five hundred twenty thousand, one hundred thirty-four".
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