Base | Representation |
---|---|
bin | 100000111111011100… |
… | …000001101101101111 |
3 | 10101102202121012020000 |
4 | 200333130001231233 |
5 | 1040022024100111 |
6 | 24135032155343 |
7 | 2362561312536 |
oct | 407734015557 |
9 | 111382535200 |
10 | 35424050031 |
11 | 14028a53107 |
12 | 6a47538b53 |
13 | 3457035c66 |
14 | 1a0097131d |
15 | dc4de4c56 |
hex | 83f701b6f |
35424050031 has 20 divisors (see below), whose sum is σ = 54148050792. Its totient is φ = 23066821008.
The previous prime is 35424050029. The next prime is 35424050087. The reversal of 35424050031 is 13005042453.
35424050031 is a `hidden beast` number, since 3 + 542 + 40 + 50 + 0 + 31 = 666.
It is not a de Polignac number, because 35424050031 - 21 = 35424050029 is a prime.
It is a super-3 number, since 3×354240500313 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 35424049977 and 35424050004.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (35424050131) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 5081796 + ... + 5088761.
Almost surely, 235424050031 is an apocalyptic number.
35424050031 is a deficient number, since it is larger than the sum of its proper divisors (18724000761).
35424050031 is a wasteful number, since it uses less digits than its factorization.
35424050031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10170612 (or 10170603 counting only the distinct ones).
The product of its (nonzero) digits is 7200, while the sum is 27.
Adding to 35424050031 its reverse (13005042453), we get a palindrome (48429092484).
The spelling of 35424050031 in words is "thirty-five billion, four hundred twenty-four million, fifty thousand, thirty-one".
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