3542444440013 has 4 divisors (see below), whose sum is σ = 3582247186620. Its totient is φ = 3502641693408.

The previous prime is 3542444440001. The next prime is 3542444440079. The reversal of 3542444440013 is 3100444442453.

3542444440013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2460590665129 + 1081853774884 = 1568627^2 + 1040122^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3542444440013 is a prime.

It is a super-3 number, since 3×3542444440013³ (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3542444442013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19901373170 + ... + 19901373347.

It is an arithmetic number, because the mean of its divisors is an integer number (895561796655).

Almost surely, 2^{3542444440013} is an apocalyptic number.

It is an amenable number.

3542444440013 is a deficient number, since it is larger than the sum of its proper divisors (39802746607).

3542444440013 is an equidigital number, since it uses as much as digits as its factorization.

3542444440013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 39802746606.

The product of its (nonzero) digits is 368640, while the sum is 38.

Adding to 3542444440013 its reverse (3100444442453), we get a palindrome (6642888882466).

The spelling of 3542444440013 in words is "three trillion, five hundred forty-two billion, four hundred forty-four million, four hundred forty thousand, thirteen".