Base | Representation |
---|---|
bin | 110011100011001101011… |
… | …101011111110010001000 |
3 | 110112122210220221110020001 |
4 | 303203031131133302020 |
5 | 431020020012113134 |
6 | 11311222503412344 |
7 | 513636312065140 |
oct | 63431535376210 |
9 | 13478726843201 |
10 | 3542500113544 |
11 | 1146402a63557 |
12 | 4926881540b4 |
13 | 1c909699c252 |
14 | c365a767920 |
15 | 622365ad414 |
hex | 338cd75fc88 |
3542500113544 has 64 divisors (see below), whose sum is σ = 7796922019200. Its totient is φ = 1477051490304.
The previous prime is 3542500113539. The next prime is 3542500113589. The reversal of 3542500113544 is 4453110052453.
It is a super-3 number, since 3×35425001135443 (a number of 39 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (37).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25580232 + ... + 25718344.
It is an arithmetic number, because the mean of its divisors is an integer number (121826906550).
Almost surely, 23542500113544 is an apocalyptic number.
It is an amenable number.
3542500113544 is an abundant number, since it is smaller than the sum of its proper divisors (4254421905656).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3542500113544 is a wasteful number, since it uses less digits than its factorization.
3542500113544 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 150542 (or 150538 counting only the distinct ones).
The product of its (nonzero) digits is 144000, while the sum is 37.
Adding to 3542500113544 its reverse (4453110052453), we get a palindrome (7995610165997).
The spelling of 3542500113544 in words is "three trillion, five hundred forty-two billion, five hundred million, one hundred thirteen thousand, five hundred forty-four".
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