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35425141537 is a prime number
BaseRepresentation
bin100000111111100000…
…001100001100100001
310101102211122122111011
4200333200030030201
51040022314012122
624135111420521
72362603510012
oct407740141441
9111384578434
1035425141537
1114029629185
126a47984741
133457328a16
141a00b77009
15dc505d377
hex83f80c321

35425141537 has 2 divisors, whose sum is σ = 35425141538. Its totient is φ = 35425141536.

The previous prime is 35425141517. The next prime is 35425141553. The reversal of 35425141537 is 73514152453.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 26407550016 + 9017591521 = 162504^2 + 94961^2 .

It is a cyclic number.

It is not a de Polignac number, because 35425141537 - 211 = 35425139489 is a prime.

It is a super-3 number, since 3×354251415373 (a number of 33 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 35425141537.

It is not a weakly prime, because it can be changed into another prime (35425141517) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17712570768 + 17712570769.

It is an arithmetic number, because the mean of its divisors is an integer number (17712570769).

Almost surely, 235425141537 is an apocalyptic number.

It is an amenable number.

35425141537 is a deficient number, since it is larger than the sum of its proper divisors (1).

35425141537 is an equidigital number, since it uses as much as digits as its factorization.

35425141537 is an evil number, because the sum of its binary digits is even.

The product of its digits is 252000, while the sum is 40.

The spelling of 35425141537 in words is "thirty-five billion, four hundred twenty-five million, one hundred forty-one thousand, five hundred thirty-seven".